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The 1928 United States presidential election in Delaware took place on November 6, 1928. All contemporary 48 states were part of the 1928 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

Delaware was won by Republican former Secretary of Commerce Herbert Hoover of California, who was running against Democratic Governor of New York Alfred E. Smith. Hoover's running mate was Senate Majority Leader Charles Curtis of Kansas, while Smith's running mate was Senator Joseph Taylor Robinson of Arkansas.

Hoover won with a majority of 65.03% of the vote to Smith's 34.60%, a margin of 30.43%. Socialist candidate Norman Thomas finished a distant third, with 0.31%. Hoover’s performance is the best by any presidential candidate in Delaware, surpassing its nearest rival from Barack Obama in 2008 by 3.12%.[1] In this election, Delaware voted 13% to the right of the nation at-large.[2]

Results

1928 United States presidential election in Delaware[3]
Party Candidate Votes Percentage Electoral votes
Republican Herbert Hoover 68,860 65.03% 3
Democratic Alfred E. Smith 36,643 34.60% 0
Socialist Norman Thomas 329 0.31% 0
Communist William Z. Foster 56 0.06% 0
Totals 105,891 100.0% 3

Results by county

County Dem Rep Oth
Kent 5,727 8,335 27
New Castle 22,464 47,641 307
Sussex 7,163 12,884 54
STATEWIDE 35,354 68,860 388

See also

References

  1. ^ "Presidential General Election Results Comparison – Delaware". Dave Leip’s U.S. Election Atlas.
  2. ^ "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved March 31, 2023.
  3. ^ "1928 Presidential General Election Results – Delaware". Dave Leip’s U.S. Election Atlas.
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