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Election
For related races, see 1890 United States gubernatorial elections.
The 1890 New Hampshire gubernatorial election was held on November 4, 1890. Republican nominee Hiram A. Tuttle defeated Democratic nominee Charles H. Amsden with 49.26% of the vote.
General election
Candidates
Major party candidates
- Hiram A. Tuttle, Republican
- Charles H. Amsden, Democratic
Other candidates
- Josiah M. Fletcher, Prohibition
Results
Party | Candidate | Votes | % | ±% | |
---|---|---|---|---|---|
Republican | Hiram A. Tuttle | 42,479 | 49.26% | ||
Democratic | Charles H. Amsden | 42,386 | 49.15% | ||
Prohibition | Josiah M. Fletcher | 1,343 | 1.56% | ||
Majority | 93 | ||||
Turnout | |||||
Republican hold | Swing |
References
- ^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved July 16, 2020.
Presidential elections | |||||
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House elections | |||||
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Legislative elections |
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