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The 1796 United States presidential election in New Hampshire took place between November 4 to December 7, 1796, as part of the 1796 United States presidential election to elect the President. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
| Elections in New Hampshire |
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New Hampshire voted for Federalist candidate and Vice President John Adams, over the Democratic-Republican candidate and Secretary of State Thomas Jefferson by a total of 78.6% margin of the popular vote, making this as one of the most voted for a presidential candidate in presidential voting history of the state of New Hampshire.
Results
| 1796 United States presidential election in New Hampshire[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Federalist | John Adams | 3,265 | 89.3% | 6 | |
| Democratic-Republican | Thomas Jefferson | 393 | 10.7% | ||
| Totals | 3,658 | 100.0% | 6 | ||
See also
References
- ^ a b "Presidential Results: National, 1796". votearchive.com. Retrieved 2024-06-20.
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| General articles | ||
| Local results | ||
| Other 1796 elections | ||
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