Bis(benzonitrile)palladium dichloride is the coordination complex with the formula PdCl2(NCC6H5)2. It is the adduct of two benzonitrile (PhCN) ligands with palladium(II) chloride. It is a yellow-brown solid that is soluble in organic solvents. The compound is a reagent and a precatalyst for reactions that require soluble Pd(II).[1] A closely related compound is bis(acetonitrile)palladium dichloride.

The complex is prepared by dissolving PdCl2 in warm benzonitrile.[2] The PhCN ligands are labile, and the complex reverts to PdCl2 in noncoordinating solvents. According to X-ray crystallography, the two PhCN ligands are mutually trans.[3]

Sample of PdCl2(PhCN)2

References

  1. ^ Jiro Tsuji; Hao Guo; Shengming Ma; Daniela Sustac Roman (2015). "Bis(benzonitrile)dichloropalladium(II)". e-EROS Encyclopedia of Reagents for Organic Synthesis. pp. 1–27. doi:10.1002/047084289X.rb101.pub3. ISBN 978-0-470-84289-8.
  2. ^ Gordon K. Anderson; Minren Lin (2007). "Bis(Benzonitrile)Dichloro Complexes of Palladium and Platinum". Inorganic Syntheses. Vol. 28. pp. 60–63. doi:10.1002/9780470132593.ch13. ISBN 978-0-470-13259-3. {{cite book}}: |journal= ignored (help)
  3. ^ Olmstead, M. M.; Wei, P.-P.; Ginwalla, A. S.; Balch, A. L. (2000). "Bis(Benzonitrile)Palladium(II) Dihalides: Structures and Cocrystallization of the Cubic Cluster Pd6Cl12 with (E)-Stilbene and with Bis(Benzonitrile)Palladium(II) Dichloride". Inorganic Chemistry. 39 (20): 4555–4559. doi:10.1021/ic0000597.