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Election in Alabama
Main article: 1828 United States presidential election
The 1828 United States presidential election in Alabama took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose five representatives, or electors, to the Electoral College, who voted for President and Vice President.
Alabama voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Alabama by a margin of 79.80%.
Results
1828 United States presidential election in Alabama[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Andrew Jackson | 16,736 | 89.89% | 5 | |
National Republican | John Quincy Adams (incumbent) | 1,878 | 10.09% | 0 | |
N/A | Other | 4 | 0.02% | 0 | |
Totals | 18,618 | 100.00% | 5 |
See also
References
- ^ "1828 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved February 28, 2013.
State and district results of the 1828 United States presidential election | ||
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