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The 1966 United States Senate election in Rhode Island took place on November 8, 1966. Incumbent Democratic U.S. Senator Claiborne Pell successfully sought re-election, defeating Republican Ruth M. Briggs with 67.66% of the vote.

Primary elections

Primary elections were held on September 13, 1966.

Democratic primary

Candidates

Results

Democratic primary results[1][2]
Party Candidate Votes %
Democratic Claiborne Pell (Incumbent) unopposed

Republican primary

Candidates

Results

Republican primary results[1][2]
Party Candidate Votes %
Republican Ruth M. Briggs 15,451 82.13%
Republican Charles H. Eden 3,363 17.87%
Total votes 18,814 100.00%

General election

Results

General election results [4][5][6][7]
Party Candidate Votes %
Democratic Claiborne Pell (Incumbent) 219,331 67.66
Republican Ruth M. Briggs 104,838 32.34
Majority 114,493 35.32
Turnout 324,169
Democratic hold

References

  1. ^ a b Congressional Quarterly 1998, p. 150.
  2. ^ a b America Votes 7, p. 372.
  3. ^ "Rhode Island". Des Moines Tribune. Des Moines, Iowa. September 14, 1966. p. 3. Retrieved July 3, 2021.
  4. ^ Clerk of the U.S. House of Representatives (1967). "Statistics of the Presidential and Congressional Election of November 8, 1966" (PDF). U.S. Government Printing Office.
  5. ^ "RI US Senate, 1966". OurCampaigns. Retrieved July 3, 2021.
  6. ^ Congressional Quarterly 1998, p. 96.
  7. ^ America Votes 7, p. 352.

Bibliography

External links


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