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Election in Louisiana
Main article: 1880 United States presidential election
The 1880 United States presidential election in Louisiana took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.
Louisiana voted for the Democratic nominee, Winfield Scott Hancock, over the Republican nominee, James A. Garfield. Hancock won the state by a margin of 24.96%.
Results
1880 United States presidential election in Louisiana[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Winfield Scott Hancock of Pennsylvania | William Hayden English of Indiana | 65,047 | 62.27% | 8 | 100.00% | ||
Republican | James Abram Garfield of Ohio | Chester Alan Arthur of New York | 38,978 | 37.31% | 0 | 0.00% | ||
Greenback | James Baird Weaver of Iowa | Barzillai Jefferson Chambers of Texas | 437 | 0.42% | 0 | 0.00% | ||
Total | 104,462 | 100.00% | 8 | 100.00% |
See also
References
Select elections in Louisiana | |||||
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General | |||||
State Senate | |||||
State House | |||||
Governor | |||||
U.S. President | |||||
U.S. Senate |
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U.S. House |
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See also: Political party strength in Louisiana |
State and district results of the 1880 United States presidential election | ||
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