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The 1804 United States presidential election in Ohio took place as part of the 1804 United States presidential election. Voters chose three representatives, or electors, to vote for president and vice president. It was the first time that Ohio took part in United States presidential election.
Results
| 1804 United States presidential election in Ohio[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | Thomas Jefferson (incumbent) | 2,593 | 87.69% | 3 | |
| Federalist | Charles Cotesworth Pinckney | 364 | 12.31% | 0 | |
| Totals | 2,957 | 100.0% | 3 | ||
References
- ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 3, 2023.
| Candidates |  | |
|---|---|---|
| General articles | ||
| Local results | ||
| Other 1804 elections | ||
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