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Election in Missouri
Main article: 1836 United States presidential election
The 1836 United States presidential election in Missouri took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Missouri voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Missouri by a margin of 19.96%.
Results
1836 United States presidential election in Missouri[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Martin Van Buren | 10,995 | 59.98% | 4 | |
Whig | Hugh White | 7,337 | 40.02% | 0 | |
Totals | 18,332 | 100.0% | 4 |
See also
References
- ^ "1836 Presidential General Election Results - Missouri". U.S. Election Atlas. Retrieved April 15, 2013.
Recent elections in Missouri | |
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Governor | |
Lieutenant Governor | |
Attorney General | |
State Auditor | |
State Treasurer | |
Secretary of State | |
MO Senate | |
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U.S. President | |
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U.S. House of Representatives | |
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State and district results of the 1836 United States presidential election | ||
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