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Neodymium(III) phosphate is an inorganic compound, with the chemical formula of NdPO4.
Properties
Neodymium(III) phosphate hemihydrate can be obtained by the reaction of neodymium(III) chloride and phosphoric acid:[1]
- NdCl3 + H3PO4 → NdPO4 + 3 HCl
Its anhydrous form can be obtained by the reaction of silicon pyrophosphate (SiP2O7) and neodymium(III) fluoride.[2]
Properties
Neodymium(III) phosphate reacts with calcium pyrophosphate to obtain Ca9Nd(PO4)7.[3]
References
- ^ Hukuo, Keniti; Hikichi, Yasuo. Syntheses of rare earth orthophosphates (RPO4·nH2O, R = La-Yb, n = 0-2). Nagoya Kogyo Daigaku Gakuho, 1980. 31: 175-182. ISSN 0369-3171.
- ^ Carlos E. Bamberger, George M. Begun, Dale E. Heatherly (November 1983). "Synthesis of Metal Phosphates Using SiP2O7". Journal of the American Ceramic Society. 66 (11): c208–c209. doi:10.1111/j.1151-2916.1983.tb10575.x. ISSN 0002-7820. Retrieved 2022-03-06.
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: CS1 maint: multiple names: authors list (link) - ^ Teterskii, A. V.; Morozov, V. A.; Stefanovich, S. Yu.; Lazoryak, M. V. Dielectric and nonlinear optical properties of the Ca9R(PO4)7 (R = Ln) Phosphate. Zhurnal Neorganicheskoi Khimii, 2005. 50 (7): 1072-1076.
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