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Election in Louisiana
Main article: 1852 United States presidential election
The 1852 United States presidential election in Louisiana took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.
Louisiana voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Louisiana by a narrow margin of 3.88%.
Results
1852 United States presidential election in Louisiana[1][2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Franklin Pierce of New Hampshire | William R. King of Alabama | 18,647 | 51.94% | 6 | 100.00% | ||
Whig | Winfield Scott of New Jersey | William A. Graham of North Carolina | 17,255 | 48.06% | 0 | 0.00% | ||
Total | 35,902 | 100.00% | 6 | 100.00% |
See also
References
- ^ "1852 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved December 2, 2017.
- ^ "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 2, 2017.
Select elections in Louisiana | |||||
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General | |||||
State Senate | |||||
State House | |||||
Governor | |||||
U.S. President | |||||
U.S. Senate |
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U.S. House |
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See also: Political party strength in Louisiana |
State results of the 1852 U.S. presidential election | ||
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