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Vanadium(V) chloride is the inorganic compound with the formula VCl5. It is a black diamagnetic solid. The molecules adopt a bioctahedral structure similar to that of niobium(V) chloride.[1]

Preparation and reactions

Vanadium(V) chloride is prepared from the vanadium pentafluoride with excess boron trichloride:

2 VF5 + 10 BCl3 → [VCl5]2 + 10 BF2Cl

It is unstable at room temperature with respect to vanadium(IV) chloride:

[VCl5]2 → 2 VCl4 + Cl2

In contrast, the heavier analogues NbCl5 and TaCl5 are stable and not particularly oxidizing.

References

  1. ^ Tamadon, Farhad; Seppelt, K. (2012). "The Elusive Halides VCl5, MoCl6, and ReCl6". Angewandte Chemie International Edition. 52 (2): 767–769. doi:10.1002/anie.201207552. PMID 23172658.
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