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Niobium(V) bromide is the inorganic compound with the formula Nb2Br10. Its name comes from the compound's empirical formula, NbBr5.[2] It is a diamagnetic, orange solid that hydrolyses readily. The compound adopts an edge-shared bioctahedral structure, which means that two NbBr5 units are joined by a pair of bromide bridges. There is no bond between the Nb centres.[3] Niobium(V) chloride, niobium(V) iodide, tantalum(V) chloride, tantalum(V) bromide, and tantalum(V) iodide all share this structural motif.

Synthesis

Niobium(V) bromide can be prepared by the reaction of bromine with niobium metal at 230-250 °C in a tube furnace. It can also be produced from the more accessible oxide by metathesis using aluminium tribromide:[4]

Nb2O5 + 3.3 AlBr3 → 2 NbBr5 + 3.3 Al2O3

A challenge with the latter method is the occurrence of NbOBr3 as an impurity.

References

  1. ^ "Niobium(V) bromide". pubchem.ncbi.nlm.nih.gov. Retrieved 28 December 2021.
  2. ^ Greenwood, N. N.; & Earnshaw, A. (1997). Chemistry of the Elements (2nd Edn.), Oxford: Butterworth-Heinemann. ISBN 0-7506-3365-4.
  3. ^ Hönle, Wolfgang; Furuseth, Sigrid; Schnering, Hans Georg von (1990). "Synthesis and Crystal Structure of Ordered, Orthorhombic α-NbBr5". Zeitschrift für Naturforschung B. 45 (7): 952–956. doi:10.1515/znb-1990-0706. S2CID 98293250.
  4. ^ G. Brauer (1963). "Niobium(V) and Tantalum(V) Bromides". In G. Brauer (ed.). Handbook of Preparative Inorganic Chemistry, 2nd Ed. Vol. 1. NY, NY: Academic Press. p. 1311.

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