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by | Mar 16, 2018 | Hosta

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Iridium(IV) iodide is a binary chemical compound of iridium and iodide with the chemical formula IrI
4.[1][2][3]

Preparation

Iridium(IV) iodide can be obtained by reacting dipotassium hexachloroiridate or hexachloroiridic acid with an aqueous solution of potassium iodide.[4][5]

Properties

Iridium tetraiodide forms black crystals, does not dissolve in water and alcohol.[6][7][8] In alkali metal iodide solutions, the compound dissolves easily to give a ruby red solution, forming complex salts.[5]

The compound decomposes when heated:[citation needed]

IrI4 → Ir + 2I2

Uses

Iridium(IV) iodide can be used as a catalyst in organic chemistry.[9][8]

References

  1. ^ "CAS 7790-45-6 Iridium tetraiodide - Alfa Chemistry". alfa-chemistry.com. Retrieved 3 May 2023.
  2. ^ "Iridium tetraiodide". American Elements. Retrieved 3 May 2023.
  3. ^ Macintyre, Jane E. (23 July 1992). Dictionary of Inorganic Compounds. CRC Press. p. 3507. ISBN 978-0-412-30120-9. Retrieved 3 May 2023.
  4. ^ "Studies on iridium compounds". discover.dtic.mil. Retrieved 2023-10-16.
  5. ^ a b Kandiner, H. J. (2013-09-03). Iridium (in German). Springer-Verlag. ISBN 978-3-662-12128-3.
  6. ^ Comey, Arthur Messenger (1896). A Dictionary of Chemical Solubilities Inorganic: xx, 515 p. Macmillan & Company. p. 193. Retrieved 3 May 2023.
  7. ^ Roscoe, Henry Enfield; Schorlemmer, Carl (1895). A Treatise on Chemistry. D. Appleton. p. 445.
  8. ^ a b "Iridium(IV) iodide". Alfa Aesar. Retrieved 3 May 2023.
  9. ^ Nobel, Dominique (8 August 1996). "Method for preparing iridium iodides and use thereof as catalysts". Retrieved 3 May 2023.
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