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The 1996 Romanian Open was a men's tennis tournament played on outdoor clay courts at the Arenele BNR in Bucharest, Romania that was part of the World Series of the 1996 ATP Tour. It was the fourth edition of the tournament and was held from 9 September until 15 September 1996. Fourth-seeded Alberto Berasategui won the singles title.[3]

Finals

Singles

Spain Alberto Berasategui defeated Spain Carlos Moyá 6–1, 7–6(7–5)

  • It was Berasategui's third title of the year and the 12th of his career.

Doubles

Sweden David Ekerot / United States Jeff Tarango defeated South Africa David Adams / Netherlands Menno Oosting 7–6, 7–6

  • It was Ekerot's second title of the year and of his career. It was Tarango's second title of the year and fifth of his career.

References

  1. ^ "1996 Bucharest – Singles draw". Association of Tennis Professionals (ATP).
  2. ^ "1996 Bucharest – Doubles draw". Association of Tennis Professionals (ATP).
  3. ^ John Barrett, ed. (1997). International Tennis Federation World of Tennis 1997. London: CollinsWillow. pp. 131, 151. ISBN 9780002187145.

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