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Partial general elections were held in Belgium on 10 June 1890.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 94 of the 138 seats.[2]

Under the alternating system, elections were held in only four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders. Thus, only 69 seats out of the 138 were up for election. Additionally, a special election was held in Neufchâteau on 3 June 1890.[3]

Results

Chamber of Representatives

PartyVotes%Seats
WonTotal+/–
Liberal Party20,82954.514044+4
Catholic Party17,25345.152994–4
Belgian Labour Party980.2600New
Others300.08000
Total38,210100.00691380
Total votes38,210
Registered voters/turnout59,45264.27
Source: Mackie & Rose,[4] Sternberger et al.

Constituencies

The distribution of seats among the electoral districts was as follows:[5]

Province Arrondissement Seats
Antwerp Antwerp 8
Mechelen 3
Turnhout 3
Limburg Hasselt 2
Maaseik 1
Tongeren 2
East Flanders Aalst 4
Oudenaarde 3
Gent 8
Eeklo 1
Dendermonde 3
Sint-Niklaas 3
West Flanders Bruges 3
Roeselare 2
Tielt 2
Kortrijk 4
Ypres 3
Veurne 1
Diksmuide 1
Ostend 1
Brabant Leuven 5
Brussels 16
Nivelles 4
Hainaut Tournai 4
Ath 2
Charleroi 7
Thuin 3
Mons 6
Soignies 3
Liège Huy 2
Waremme 2
Liège 9
Verviers 4
Luxembourg Arlon 1
Marche 1
Bastogne 1
Neufchâteau 1
Virton 1
Namur Namur 4
Dinant 2
Philippeville 2

References

  1. ^ Codebook Constituency-level Elections Archive, 2003
  2. ^ a b Sternberger, D, Vogel, B & Nohlen, D (1969) Die Wahl der Parlamente: Band I: Europa - Erster Halbband, p105
  3. ^ Opening session of 8 July 1890
  4. ^ Thomas T. Mackie & Richard Rose (1991) The International Almanac of Electoral History, Macmillan, pp50–51
  5. ^ List of members of the Chamber of Representatives (1890-1891)
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