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| Elections in Illinois |
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The 1884 United States presidential election in Illinois took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose 22 representatives, or electors to the Electoral College, who voted for president and vice president.
Illinois voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a narrow margin of 3.74%.[1]
This is the first of only three elections in the history of the party that a Democrat won the presidency without winning Illinois (the others being 1916 and 1976).[2]
Results
| 1884 United States presidential election in Illinois[3] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | James Gillespie Blaine of Maine | John Alexander Logan of Illinois | 337,469 | 50.17% | 22 | 100.00% | ||
| Democratic | Grover Cleveland of New York | Thomas Andrews Hendricks of Indiana | 312,351 | 46.43% | 0 | 0.00% | ||
| Prohibition | John Pierce St. John of Kansas | William Daniel of Maryland | 12,074 | 1.79% | 0 | 0.00% | ||
| Greenback | Benjamin Franklin Butler of Massachusetts | Absolom Madden West of Mississippi | 10,776 | 1.60% | 0 | 0.00% | ||
| Total | 672,670 | 100.00% | 22 | 100.00% | ||||
See also
References
- ^ "True Republican 12 December 1888 — Illinois Digital Newspaper Collections". idnc.library.illinois.edu. Retrieved December 3, 2021.
- ^ "Historical U.S. Presidential Elections 1789-2020". 270toWin.com. Retrieved December 17, 2021.
- ^ "1884 Presidential General Election Results - Illinois". U.S. Election Atlas. Retrieved December 23, 2013.
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