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| Elections in Delaware |
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The 1880 United States presidential election in Delaware took place on November 2, 1880, as part of the 1880 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.[1]
Delaware was won by General Winfield Scott Hancock (D–Pennsylvania), running with former Representative William Hayden English, with 51.53% of the popular vote, against Representative James A. Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 48.03% of the vote.[1]
As of 2023, this is the most recent time that a Republican won the presidency without carrying Sussex County.
Results
| 1880 United States presidential election in Delaware[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Winfield Scott Hancock of Pennsylvania | William Hayden English of Indiana | 15,181 | 51.53% | 3 | 100.00% | ||
| Republican | James A. Garfield of Ohio | Chester A. Arthur of New York | 14,148 | 48.03% | 0 | 0.00% | ||
| Greenback | James B. Weaver of Iowa | Barzillai J. Chambers of Texas | 129 | 0.44% | 0 | 0.00% | ||
| Total | 18,345 | 100.00% | 3 | 100.00% | ||||
See also
References
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