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Election in Delaware
Main article: 1876 United States presidential election
The 1876 United States presidential election in Delaware took place on November 7, 1876, as part of the 1876 United States presidential election. Delaware voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.[1]
Delaware was won by Samuel J. Tilden, the former governor of New York (D–New York), running with Thomas A. Hendricks, the governor of Indiana and future vice president, with 55.45% of the popular vote, against Rutherford B. Hayes, the governor of Ohio (R-Ohio), running with Representative William A. Wheeler, with 44.55% of the vote.[1]
Results
1876 United States presidential election in Delaware[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Samuel J. Tilden of New York | Thomas A. Hendricks of Indiana | 13,381 | 55.45% | 10 | 100.00% | ||
Republican | Rutherford B. Hayes of Ohio | William A. Wheeler of New York | 10,752 | 44.55% | 0 | 0.00% | ||
Total | 24,133 | 100.00% | 3 | 100.00% |
See also
References
General | |
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Del. Senate | |
Del. House | |
Governor |
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U.S. President |
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U.S. Senate Class 1 | |
U.S. Senate Class 2 | |
U.S. House |
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See also: Political party strength in Delaware |
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State and district results of the 1876 United States presidential election | ||
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