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Election in Connecticut
Main article: 1860 United States presidential election
The 1860 United States presidential election in Connecticut took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose six electors of the Electoral College, who voted for president and vice president.
Connecticut was won by Republican candidate Abraham Lincoln, who won by a margin of 32.36%.
Results
1860 United States presidential election in Connecticut[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | Abraham Lincoln of Illinois | Hannibal Hamlin of Maine | 43,486 | 53.86% | 6 | 100.00% | ||
Democratic | Stephen Arnold Douglas of Illinois | Herschel Vespasian Johnson of Georgia | 17,364 | 21.50% | 0 | 0.00% | ||
Southern Democratic | John Cabell Breckinridge of Kentucky | Joseph Lane of Oregon | 16,558 | 20.51% | 0 | 0.00% | ||
Constitutional Union | John Bell of Tennessee | Edward Everett of Massachusetts | 3,337 | 4.13% | 0 | 0.00% | ||
Total | 80,745 | 100.00% | 6 | 100.00% |
See also
References
- ^ "1860 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved December 24, 2013.
General | |
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State Senate | |
State House | |
Governor |
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U.S. President | |
U.S. Senate |
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U.S. House |
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See also: Political party strength in Connecticut |
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State results of the 1860 U.S. presidential election | ||
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