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Election in Louisiana
Main article: 1832 United States presidential election
The 1832 United States presidential election in Louisiana took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
Louisiana voted for the Democratic Party candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Louisiana by a margin of 23.34%.
Results
1832 United States presidential election in Louisiana[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Andrew Jackson (incumbent) | 3,908 | 61.67% | 5 | |
National Republican | Henry Clay | 2,429 | 38.33% | 0 | |
Totals | 6,337 | 100.0% | 5 |
See also
References
- ^ "1832 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved April 12, 2013.
President | |
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U.S. Senate | |
U.S. House |
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Governors | |
Mayors | |
States and territories |
Select elections in Louisiana | |||||
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General | |||||
State Senate | |||||
State House | |||||
Governor | |||||
U.S. President | |||||
U.S. Senate |
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U.S. House |
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See also: Political party strength in Louisiana |
State and district results of the 1832 United States presidential election | ||
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