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| Elections in New Jersey |
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The 1828 United States presidential election in New Jersey took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.
New Jersey voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won New Jersey by a narrow margin of 4.26%.
Results
| 1828 United States presidential election in New Jersey[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| National Republican | John Quincy Adams (incumbent) | 23,753 | 52.12% | 8 | |
| Democratic | Andrew Jackson | 21,809 | 47.86% | 0 | |
| N/A | Other | 8 | 0.02% | 0 | |
| Totals | 45,570 | 100.0% | 8 | ||
See also
References
- ^ "1828 Presidential General Election Results - New Jersey". U.S. Election Atlas. Retrieved February 28, 2013.
State and district results of the 1828 United States presidential election | ||
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