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Election in Illinois
Main article: 1828 United States presidential election
The 1828 United States presidential election in Illinois took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Illinois voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Illinois by a margin of 34.44%.
Results
1828 United States presidential election in Illinois[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Andrew Jackson | 9,560 | 67.22% | 3 | |
National Republican | John Quincy Adams (incumbent) | 4,662 | 32.78% | 0 | |
Totals | 14,222 | 100.0% | 3 |
See also
References
- ^ "1828 Presidential General Election Results - Illinois". U.S. Election Atlas. Retrieved February 28, 2013.
State and district results of the 1828 United States presidential election | ||
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By year | |
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Presidential |
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U.S. Senate | |
U.S. House | |
Special | |
Gubernatorial | |
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Other state executive offices | |
State Senate | |
State House | |
State judicial | |
Ballot measures and referendums |
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Chicago mayoral |
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Chicago City Council | |
Other municipal | |
Cook County |
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