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Election in Arkansas
Main article: 1856 United States presidential election
The 1856 United States presidential election in Arkansas was held on November 4, 1856. Arkansas voters chose four electors to represent the state in the Electoral College, which chose the president and vice president.
Arkansas voted for the Democratic nominee James Buchanan, who received 67% of the vote.[1]
Republican Party nominee John C. Frémont was not on the ballot.
Results
Party | Candidate | Votes | % | |
---|---|---|---|---|
Democratic | James Buchanan | 21,910 | 67.12% | |
Know Nothing | Millard Fillmore | 10,732 | 32.88% | |
Total votes | 32,642 | 100% |
See also
References
- ^ "1856 Presidential General Election Results - Arkansas". David Leip's U.S. Election Atlas. Retrieved 2017-06-05.
General |
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Governor |
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U.S. President | |
U.S. Senate |
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U.S. House |
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'S,' denotes special election; 'U,' denotes election under Federal (Union) military occupation See also: Political party strength in Arkansas |
State results of the 1856 U.S. presidential election | ||
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