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Election in Missouri
Main article: 1840 United States presidential election
The 1840 United States presidential election in Missouri took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Missouri voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Missouri by a margin of 13.26%.
Results
1840 United States presidential election in Missouri[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 29,969 | 56.63% | 4 | 100.00% | ||
Whig | William Henry Harrison of Ohio | John Tyler of Virginia | 22,954 | 43.37% | 0 | 0.00% | ||
Total | 52,923 | 100.00% | 4 | 100.00% |
See also
References
- ^ "1840 Presidential General Election Results - Missouri". Dave Leip's Atlas of U.S. Presidential Elections. Retrieved December 23, 2013.
Recent elections in Missouri | |
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Lieutenant Governor | |
Attorney General | |
State Auditor | |
State Treasurer | |
Secretary of State | |
MO Senate | |
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U.S. President | |
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State and district results of the 1840 United States presidential election | ||
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