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Election in South Carolina
Main article: 1884 United States presidential election
The 1884 United States presidential election in South Carolina took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose 9 representatives, or electors to the Electoral College, who voted for president and vice president.
South Carolina voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine. Cleveland won the state by a wide margin of 51.84%.
Results
1884 United States presidential election in South Carolina[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Grover Cleveland of New York | Thomas Andrews Hendricks of Indiana | 69,845 | 75.25% | 9 | 100.00% | ||
Republican | James Gillespie Blaine of Maine | John Alexander Logan of Illinois | 21,730 | 23.41% | 0 | 0.00% | ||
N/A | Others | Others | 1,237 | 1.33% | 0 | 0.00% | ||
Total | 92,812 | 100.00% | 9 | 100.00% |
References
- ^ "1884 Presidential General Election Results - South Carolina". U.S. Election Atlas. Retrieved December 23, 2013.
General |
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State Senate | |
State House | |
Governor | |
U.S. President | |
U.S. Senate |
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U.S. House |
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State and district results of the 1884 United States presidential election | ||
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