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First-seeded Shirley Fry defeated Althea Gibson 6–3, 6–4 in the final to win the women's singles tennis title at the 1956 U.S. National Championships.[2][3]

Seeds

The seeded players are listed below. Shirley Fry is the champion; others show in brackets the round in which they were eliminated.

  1. United States Shirley Fry (champion)
  2. United States Althea Gibson (finalist)
  3. United States Louise Brough (quarterfinals)
  4. United States Dorothy Knode (quarterfinals)
  5. United States Margaret duPont (quarterfinals)
  6. United Kingdom Shirley Bloomer (semifinals)
  7. United States Betty Pratt (semifinals)
  8. United States Darlene Hard (quarterfinals)

Draw

Key

Final eight

Quarterfinals Semifinals Finals
               
1 United States Shirley Fry 6 4 6
5 United States Margaret duPont 2 6 3
1 United States Shirley Fry 6 6
6 United Kingdom Shirley Bloomer 4 4
6 United Kingdom Shirley Bloomer 6 6
3 United States Louise Brough 3 3
1 United States Shirley Fry 6 6
2 United States Althea Gibson 3 4
4 United States Dorothy Knode 6 0 2
7 United States Betty Pratt 4 6 6
8 United States Betty Pratt 1 8
2 United States Althea Gibson 6 10
8 United States Darlene Hard 7 1
2 United States Althea Gibson 9 6

References

  1. ^ a b Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 471. ISBN 978-0942257700.
  2. ^ G.P. Hughes, ed. (1957). Dunlop Lawn Tennis Annual 1957. London: Ed. J. Burrow & Co. Ltd. pp. 245–247.
  3. ^ "National Tennis Championships Opens Today". The Free Lance–Star. AP. August 31, 1956. p. 12.
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