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The 1800 United States presidential election in Rhode Island took place as part of the 1800 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College who voted for president and vice president.

Rhode Island voted for the Federalist candidate, John Adams, over the Democratic-Republican candidate, Thomas Jefferson. Adams won Rhode Island by a margin of 4.3%. All 4 Adams electors received more votes than the 4 Jefferson electors and the electoral vote was all for Adams in Rhode Island.

Results

1800 United States presidential election in Rhode Island [1]
Party Candidate Votes Percentage Electoral votes
Federalist John Adams (incumbent) 2,353 52.15% 4
Democratic-Republican Thomas Jefferson 2,159 47.85% 0
Totals 4,512 100.0% 4

See also

References

  1. ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved April 25, 2022.


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