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Election in Arkansas
Main article: 1844 United States presidential election
The 1844 United States presidential election in Arkansas took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.
Arkansas voted for the Democratic candidate, James K. Polk, over Whig candidate Henry Clay. Polk won Arkansas by a margin of 26.02%.
Results
1844 United States presidential election in Arkansas[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 9,546 | 63.01% | 3 | 100.00% | ||
Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 5,604 | 36.99% | 0 | 0.00% | ||
Total | 15,150 | 100.00% | 3 | 100.00% |
See also
References
- ^ "1844 Presidential General Election Results - Arkansas". U.S. Election Atlas. Retrieved December 23, 2013.
General |
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Governor |
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U.S. President | |
U.S. Senate |
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U.S. House |
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'S,' denotes special election; 'U,' denotes election under Federal (Union) military occupation See also: Political party strength in Arkansas |
State and district results of the 1844 United States presidential election | ||
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